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Hrishant Goswami Grade: 10
         A copper wire of cross-sectional area 0.01 cm2 is under a tension of 20 N. Find the decrease in the cross-sectional area. Young modulus of copper = 1.1 × 1011 N m-2 and Poisson ratio = 0.32. [Hint: ∆A/A=2 ∆r/r]    
3 years ago

Answers : (1)

Deepak Patra
askIITians Faculty
474 Points
										Sol. Y = FL/A∆L ⇒  ∆L/L = F/Ay

σ = ∆D/D/∆L/L ⇒ ∆D
again, ∆A/A = 2∆r/r
⇒ ∆A = 2∆r/r
3 years ago
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