A burglar’s car had a start with an accelaration of 2 m/s^2. A police vigilant party came in a car to the spot at a velocity of 20 m/s after 3.75 sec and continued to chase the bulgar’s car with uniform velocity. Find the time in which the police van will overtake the car.

Question

Carmel Emmanuel · Answer

Distance covered by burglar in 3.75 S=1/2at 2 =14.06 Velocity of burglar at that moment=at=7.50 At this time police arrived Let t be time to overtake u relative =20-7.5=12.5 Now apply equation of motion S f - S i =u relative t+1/2a relative t 2 s f =0 Si=14.06 Find out the roots of t

Priya · Answer

u=0 a=2 S = ut+1/2at^2 20t= 0(t+5)+ 1/2×2(t+5)^2 20t=(t+5)^2 20t=t^2+25+10t t^2-10t+25=0 (t-5)^2=0 t-5=0 t=5sec

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A burglar’s car had a start with an accelaration of 2 m/s^2. A police vigilant party came in a car to the spot at a velocity of 20 m/s after 3.75 sec and continued to chase the bulgar’s car with uniform velocity. Find the time in which the police van will overtake the car.

A burglar’s car had a start with an accelaration of 2 m/s^2. A police vigilant party came in a car to the spot at a velocity of 20 m/s after 3.75 sec and continued to chase the bulgar’s car with uniform velocity. Find the time in which the police van will overtake the car.

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A burglar’s car had a start with an accelaration of 2 m/s^2. A police vigilant party came in a car to the spot at a velocity of 20 m/s after 3.75 sec and continued to chase the bulgar’s car with uniform velocity. Find the time in which the police van will overtake the car.

A burglar’s car had a start with an accelaration of 2 m/s^2. A police vigilant party came in a car to the spot at a velocity of 20 m/s after 3.75 sec and continued to chase the bulgar’s car with uniform velocity. Find the time in which the police van will overtake the car.

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