A body is projected with a velocity 60m/s at 30 to horizontal. Its velocity after 3 sec?

Question

Aman gohel · Answer

X component,Ux=ucos30=60cos30. =30√3m/s. Y component,Uy=usin30=60*0.5. =30m/sVelocity after 3 s, Vy=Uy-gt =>Vy=30-10*3 =>Vy=0Resultant velocity,R=√((30√3)^2+0^2)[According to triangle`s law of vector addition]=>R=52m/s(Ans)

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A body is projected with a velocity 60m/s at 30 to horizontal. Its velocity after 3 sec?

A body is projected with a velocity 60m/s at 30 to horizontal. Its velocity after 3 sec?

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A body is projected with a velocity 60m/s at 30 to horizontal. Its velocity after 3 sec?

A body is projected with a velocity 60m/s at 30 to horizontal. Its velocity after 3 sec?

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