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```        If alpha is the angle of limiting friction, then the minimum force required to pull a block of mass m kept on the horizontal surface is?
Ans mgsin(theta)```
7 years ago

147 Points
```										Dear Nehal
Let a force F is applied on the block at an angel x from the horizontal
normal force will be N =mg - Fsinx
so Fcosx =μN
Fcosx =μ(mg - Fsinx)
F =μmg/(cosx +μsinx)
for minim F   , (cosx +μsinx)  will be maximum so  (cosx +μsinx)=√(1+μ2)
So  F min = μmg/√(1+μ2)
here μ = tanΘ
so F min = tanΘmg/√(1+tan2Θ)
=mgsinΘ
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```
7 years ago
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