A particle moves under the force F(x) = (x 2 - 6x)N, where x is in metres. For small displacements from the origin what is the force constant in the simple harmonic approximation ??

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Ramesh V · Answer

aas F=-kx k= -dF/dx = -(2x-6) as x tends to 1, we have k=6N/m -- regards Ramesh

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A particle moves under the force F(x) = (x 2 - 6x)N, where x is in metres. For small displacements from the origin what is the force constant in the simple harmonic approximation ??

A particle moves under the force F(x) = (x² - 6x)N, where x is in metres. For small displacements from the origin what is the force constant in the simple harmonic approximation ??

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A particle moves under the force F(x) = (x 2 - 6x)N, where x is in metres. For small displacements from the origin what is the force constant in the simple harmonic approximation ??

A particle moves under the force F(x) = (x2 - 6x)N, where x is in metres. For small displacements from the origin what is the force constant in the simple harmonic approximation ??

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A particle moves under the force F(x) = (x² - 6x)N, where x is in metres. For small displacements from the origin what is the force constant in the simple harmonic approximation ??