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A man raises a bucket of water of mass 10 kg from a well. When the bucket has risen 18 m, its velocity is 16 m/s. Work done by the man is (take g = 10 m/s2)

        (A)    3080 J

        (B)    1280 J

        (C)    1380 J

        (D)    1800 J

6 years ago


Answers : (2)


Dear ishika

work done by man = increse in total energy of bucket

                           =mgh + 1/2 m v2

                          = 10*10*18   + 1/2  * 10 * 162

                          = 3080 j

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6 years ago

 Dear ishika,



work done = potential energy+ kinetic energy.

                       = mgh + 1/2(mv2)

                        = (10×10×18)+[1⁄2×(162)].

                        = 3080 J


Thanks ans regards

Akhilesh Shukla

6 years ago

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