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```
A man raises a bucket of water of mass 10 kg from a well. When the bucket has risen 18 m, its velocity is 16 m/s. Work done by the man is (take g = 10 m/s2)
(A)    3080 J
(B)    1280 J
(C)    1380 J
(D)    1800 J

```
7 years ago

147 Points
```										Dear ishika

work done by man = increse in total energy of bucket
=mgh + 1/2 m v2
= 10*10*18   + 1/2  * 10 * 162
= 3080 j

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```
7 years ago
396 Points
```										 Dear ishika,

since
work done = potential energy+ kinetic energy.
= mgh + 1/2(mv2)
= (10×10×18)+[1⁄2×(162)].
= 3080 J

Thanks ans regards
Akhilesh Shukla

```
7 years ago
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