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A man raises a bucket of water of mass 10 kg from a well. When the bucket has risen 18 m, its velocity is 16 m/s. Work done by the man is (take g = 10 m/s2)
(A) 3080 J
(B) 1280 J
(C) 1380 J
(D) 1800 J
Dear ishika
work done by man = increse in total energy of bucket
=mgh + 1/2 m v2
= 10*10*18 + 1/2 * 10 * 162
= 3080 j
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Dear ishika,
since
work done = potential energy+ kinetic energy.
= mgh + 1/2(mv2)
= (10×10×18)+[1⁄2×(162)].
= 3080 J
Thanks ans regards
Akhilesh Shukla
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