MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: R

There are no items in this cart.
Continue Shopping
Menu
ishika mathur Grade:
        


A man raises a bucket of water of mass 10 kg from a well. When the bucket has risen 18 m, its velocity is 16 m/s. Work done by the man is (take g = 10 m/s2)


        (A)    3080 J


        (B)    1280 J


        (C)    1380 J


        (D)    1800 J



7 years ago

Answers : (2)

Badiuddin askIITians.ismu Expert
147 Points
										

Dear ishika




work done by man = increse in total energy of bucket


                           =mgh + 1/2 m v2


                          = 10*10*18   + 1/2  * 10 * 162


                          = 3080 j




Please feel free to post as many doubts on our discussion forum as you can.
If you find any question Difficult to understand - post it here and we will get you
the answer and detailed  solution very  quickly.

 We are all IITians and here to help you in your IIT JEE preparation.

All the best.
 
Regards,
Askiitians Experts
Badiuddin

7 years ago
Aditi Chauhan
askIITians Faculty
396 Points
										

 Dear ishika,


 


since


work done = potential energy+ kinetic energy.


                       = mgh + 1/2(mv2)


                        = (10×10×18)+[1⁄2×(162)].


                        = 3080 J


 


Thanks ans regards


Akhilesh Shukla



7 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete Physics Course - Class 12
  • OFFERED PRICE: R 2,600
  • View Details
Get extra R 2,500 off
USE CODE: SSP11
  • Complete Physics Course - Class 11
  • OFFERED PRICE: R 2,800
  • View Details
Get extra R 2,500 off
USE CODE: SSP11

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details