Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
a disc of mass M and radius R is rolling purely with center's velocity v0 on a flat horizontal floor when it hits a step in the floor of height R/4 .the corner of the step is sufficiently rough to prevent any slipping of the disc against itself.what is the velocity of the disc just after the impact?
Dear akash
initially it is purelly rorating
so w=v/R
initial angular momentum about point A
Li = I (Vo/R) + mV0 (3R/4)
= MRVo/2 + 3/4MRVo
= 5/4MRVo
just after the impact sphear start rorating about point A
Lf = MV1R
so
5/4MRVo = MV1R
V1 =5/4V0
Please feel free to post as many doubts on our discussion forum as you can.If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly.We are all IITians and here to help you in your IIT JEE & AIEEE preparation.All the best. Regards,Askiitians ExpertsBadiuddin
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !