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akash kashyp Grade: Upto college level
        

a disc of mass M and radius R is rolling purely with center's velocity v0 on a flat horizontal floor when it hits a step in the floor of height R/4 .the corner of the  step is sufficiently rough to prevent any slipping of the disc against itself.what is the velocity of the disc just after the impact?

7 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
										

Dear akash


 


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initially it is purelly rorating


so w=v/R


initial angular momentum about point A


Li = I (Vo/R)  + mV0 (3R/4)


   = MRVo/2  + 3/4MRVo


  = 5/4MRVo


just after the impact sphear start rorating about point A


Lf  = MV1R


 so


 5/4MRVo  = MV1R


 V1 =5/4V0


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7 years ago
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