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Chilukuri Sai Kartik Grade: 12
        

A car moving with const. acceleration covered distance between 2 points 60m apart in 6 sec. Its speed as it  passes 2nd point was 15 m/s.


1)At what prior distance from the first point was the car at rest?


2)Plot graph between s and t between v and t, starting from rest ?


Plz.Explain...

7 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
										

Dear Chilukuri


let the velocity of car at first point is v


and at x prior distance from first point car was in the rest.


motion between first and second point


15=v +a*6 ......................1


and


60 =v(6) +1/2 *a* (6)2


10=v +3a ..........................2


solve equation 1 and 2


a=5/3


v=5


now motion between fron point of rest to first point


52 =02 +2*a*x


x=15/4 m


 


 


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Badiuddin


 

7 years ago
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