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ramya bhaskar Grade: 11
        

A wedge shaped block 'A' of mass 'M' is at rest on a smooth horizontal surface.A small block 'B' of mass  'm' placed at the top edge of inclined plane of length 'L' as shown in the figure.By the time, the block 'B' reaches the bottom end the wedge 'A' will move a distance of  

7 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
										

Dear ramya


Since there is no external force in horizontal direction in wedge + mass system


so center of mass of wedge + mass syaytem will not move


 


6065-411_7662_1345.JPG


let x1 is the COM of wedge from origin


 and x is the distance moved by wedge


(Mx1 +mLcosΘ)/(m+M)   =  {M(x1+x) + mx}/(m+M)


x=mLcos Θ/(m+M)





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Badiuddin

7 years ago
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