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pallavi pradeep bhardwaj Grade: 12
        

A mass m=100gm is attached at the end of  a light spring which oscillates on a fictionless horizontal table with an amplitude equal to 0.16m and time period equal to 2sec Initially the mass is released from rest at t=0 and displacement x=-0.16m the expression for the displacement of the mass at any time t is

7 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
										

Dear Pallavi


Equation of SHM is given as


x=X sin(wt + Φ)   


  where  X=.16 m


  w=2∏/T


    =2∏/2


     =∏


so x=.16 sin(∏t + Φ)  


given at t=0 sec   x=-.16m


-.16= .16sin(0 + Φ) 


or sin( Φ) = -1


   or  Φ =-∏/2


so final equation is


x=.16 sin(∏t -∏/2)





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Badiuddin

7 years ago
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