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A mass m=100gm is attached at the end of a light spring which oscillates on a fictionless horizontal table with an amplitude equal to 0.16m and time period equal to 2sec Initially the mass is released from rest at t=0 and displacement x=-0.16m the expression for the displacement of the mass at any time t is
Dear Pallavi
Equation of SHM is given as
x=X sin(wt + Φ)
where X=.16 m
w=2∏/T
=2∏/2
=∏
so x=.16 sin(∏t + Φ)
given at t=0 sec x=-.16m
-.16= .16sin(0 + Φ)
or sin( Φ) = -1
or Φ =-∏/2
so final equation is
x=.16 sin(∏t -∏/2)
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