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A mass m=100gm is attached at the end of  a light spring which oscillates on a fictionless horizontal table with an amplitude equal to 0.16m and time period equal to 2sec Initially the mass is released from rest at t=0 and displacement x=-0.16m the expression for the displacement of the mass at any time t is

6 years ago


Answers : (1)


Dear Pallavi

Equation of SHM is given as

x=X sin(wt + Φ)   

  where  X=.16 m




so x=.16 sin(∏t + Φ)  

given at t=0 sec   x=-.16m

-.16= .16sin(0 + Φ) 

or sin( Φ) = -1

   or  Φ =-∏/2

so final equation is

x=.16 sin(∏t -∏/2)

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6 years ago

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