Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
        A particle executing shm of amplitude 4 cm and T=4sec The time taken by it to move from positive extreme position to half the amplitude is
8 years ago

Rohith Gandhi
24 Points
										Dear Pallavi,

Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation. All the best Pallavi !!!Regards,Askiitians ExpertsRohith Gandhi P

8 years ago
Yati Raj
24 Points
										At half distance from the extreme positions, K.E = PE1/2mv2=1/2kx2$1/2 m (A\omega cos\omega t + \phi )^{2} = 1/2 (\omega^{2}m)(A/2)^{^{2}} \Rightarrow cos^{2} \omega t = 1/4 \Rightarrow (cos 2\pi /T) t = cos\pi /3 \Rightarrow (2\pi /4) t = \pi /3 \Rightarrow t = (2/3) seconds.$ Please try to understand the answer. I  felt it as the easy way and so I am sharing it with you. as the typing of equations took me time in my computer, I made it really short. If you are going to appear for the boards, you can include a lot more steps.

11 months ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Mechanics

View all Questions »
• Complete Physics Course - Class 12
• OFFERED PRICE: Rs. 2,756
• View Details
• Complete Physics Course - Class 11
• OFFERED PRICE: Rs. 2,968
• View Details