MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
pallavi pradeep bhardwaj Grade: 12
        

The motion of the particle executing shm is given by x=0.01sin100pi(t+.05) where x in metres and time is in seconds The time period is

7 years ago

Answers : (1)

Rohith Gandhi
24 Points
										

Dear Pallavi,


x = 0.01sin(100pi*t + 5*pi) => x =  -0.01sin(100*pi*t)


 


hence from equation, omega = angular frequency = 100*pi = 2*pi/T


 


=>Time period ,  T = 2/100 = 0.02 seconds



Please feel free to post as many doubts on our discussion forum as you can. If you find any question
Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We
are all IITians and here to help you in your IIT JEE preparation.


All the best Pallavi !!!




Regards,

Askiitians Experts
Rohith Gandhi P

7 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete Physics Course - Class 12
  • OFFERED PRICE: Rs. 2,756
  • View Details
Get extra Rs. 1,185 off
USE CODE: JYOTI
  • Complete Physics Course - Class 11
  • OFFERED PRICE: Rs. 2,968
  • View Details
Get extra Rs. 1,276 off
USE CODE: JYOTI

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details