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MIHIR SHAH Grade: Upto college level
        the weight of a hollow body,made of gold,is 36.670g in air,while it is 33.865g in water. If the density of gold is 19.3 g/cc, find the volume of the hollow part of the body.(Density of water is 1 g/cc.
7 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
										

Dear mikir


weight if body =36.67 g


weight of body in water =33.865 g


this reduction in weight is dut to boyancy force


Fb = 36.67 g -33.865 g


    = 2.805 g


but Fb=wait of water replace by body


        =1*V


 


V= 2.805cc


but this total volume


so volume of hollow part + volume of solid part =V=2.805 cc


for volume of solid part


  volume of solid part*density of gold=weight of body in air


       volume of solid part=36.670/19.3 


                                    =1.9 cc


 so volume of hollow part =2.805-1.9


                                    =.905 cc





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Badiuddin


 

7 years ago
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