MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
neeraj pawar Grade: 12
        4429-1562_6544_untitled3.jpg

the corect relation b/w V1 & V2

a)V2=V1
b)V2=V1sin?
c)2V2sin?= V1
d)V2(1+sin?)=V1
7 years ago

Answers : (1)

Pratham Ashish
17 Points
										

hi,


at any time ,


let the length of string between the wedge & pully(which is stationary ) = x2


 length of string between the block  & pully (to which it is hanged ) = x1


 length of string between the both pullys =  x2/ cos(90-θ)  = x2 / sinθ


since the length of strig would be const. so the sum of upper mentioned lenght would be const.


x1 + x2 + x2/ sinθ  = const.


d/dt x1  + d/dt x2  + d/dt ( x2/ sinθ  ) = 0


v1  - v2  - v2 /sin θ   -  x2 cosθ /sin^θ  (d/dt θ) =0 .............(1)


let the height of the wedge be l,then


  tan (90 -θ) =  l / x2
 
x2 cot θ = l
 
 cotθ d/dt x2 + x2 d/dt cot θ = 0
 
-cotθ v2   - x2 cosec^2 θ (d/dt θ) =0
 
cosθ sinθ v2 + x2 (d/dt θ) = 0
 
(d/dt θ)  =  - cosθ sinθ v2 /x2 ..............put in eq . (1)
 
 
 
 v1  - v2  - v2 /sin θ   -  x2 cosθ /sin^θ  (d/dt θ) =0
 v1  - v2  - v2 /sin θ   +  x2 cosθ /sin^θ  cosθ sinθ v2 /x2  =0

 v1  - v2  - v2 /sin θ   + v2 cos^θ / sinθ   =0


v1- v2 - v2 /sinθ( 1 - cos^2θ ) = 0 


v1 -v2  - v2 sinθ =0


v1 = v2 (1 + sinθ )     (d )



 
7 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete Physics Course - Class 12
  • OFFERED PRICE: Rs. 2,756
  • View Details
Get extra Rs. 2,756 off
USE CODE: AR07
  • Complete Physics Course - Class 11
  • OFFERED PRICE: Rs. 2,968
  • View Details
Get extra Rs. 2,968 off
USE CODE: AR07

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details