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`        max height of projectile on inclined plane?`
8 years ago

Ramesh V
70 Points
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PROJECTILE FIRED FROM AN INCLINED PLANE

Consider an inclined palne which makes an  with the horizontal. Let a projectile be projected with a velocity 'v' making an angle  with the horizontal.

Let us choose X axis along the inclined plane and Y-axis perpendicular to it.

gcos and gsin are the two rectangular components of g.

Now,

vx= v cos(-) and vy = v sin(-).

Let T = time of flight of the projectile

The displacement of the projectile perpendicular to the inclined plane is clearly Zero.

Using S = ut + (1/2) a t2, for motion along y-axis, we get

0 = v sin(-) T -(1/2) g cos T2

or T = 2 v sin(-)/g cos

Range on the inclined plane is

R = 2v2 sin(-) cos/g cos2

Rmax= v2/g (1+sin)

Hmax= v2sin2(-)/2g cos

```
8 years ago
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