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A cylinder of mass M and radius R is resting on a horizontal platform(which is parallel to the x-y plane)with its axis fixed along the y axis and free to rotate about its axis. The platform is given a motion in the x direction given by x=A cos(ωt).there is no slipping between the cylinder and the platform.The max torque acting on the cylinder during its motion is?
Dear Debadutta,
acceleration a=d2x/dt2=-w2Acos(wt),lamaxl=w2A,
maximum angular acceleration=w2A/R
Torque=Iα=(MR2/2)(w2A/R)=(MRAw2/2)
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Regards,
Askiitians Experts
CHETAN MANDAYAM NAYAKAR
Hi Debadutta,
The max acn of the platform would be:
Aω2.
So max Torque, ζmax = A(MRω2)/2.
Best Regards,
Ashwin (IIT Madras).
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