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rajan jha Grade: 12
        

Two particles of masses m1 and m2 are connected by a light rod of length r to constitute a dumb-bell.The moment of inertia of the dumb=bell about an axis perpendicular to the rod passing through the center of mass of the two particles is 

6 years ago

Answers : (1)

vikas askiitian expert
510 Points
										

consider a rod , two particles of mass m1 , m2 are at its two ends then


distance of center of mass from m1 is r1= m2r/(m1+m2)       ..........1                    (using formula)


distance of center of mass from m2 is r2 = m1r/(m1+m2)          .........2


now moment of inertia of two particles is


I1 = m1r12 & I2 = m2r22


I = I1+I2 = m1r12 + m2r22            ................3


from 2 & 3 above expression becomes


I = m1m2r2/(m1+m2)


approve my ans if u like ....


also see  question new13 , i have posted the ans

6 years ago
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