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Shivam Bhagat Grade: 9
```        The displacement x of a particle along a straight line at time t is given by x = a0 + a1 t+a2t2. The acceleration of the particle is

(a)    a0

(b)    a1

(c)    2a2

(d)    a2

```
7 years ago

## Answers : (2)

vikas askiitian expert
510 Points
```										we know , v = dx/dt
a = dv/dt
x = ao + a1t + a2t2
v= dx/dt =  0 + a1 + 2a2t
a=dv/dt = d/dt (a1+2a2t)
=0+2a2
differntiation of constant is 0...
so accleration of particle = 2a2
option c is correct
```
7 years ago
Vamsi Krishna Gedela
18 Points
```										x=a0+a1t +a2t2
accn=d2x/dt2=a2
```
7 years ago
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