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Shivam Bhagat Grade: 9
        The displacement x of a particle along a straight line at time t is given by x = a0 + a1 t+a2t2. The acceleration of the particle is


(a) a0

(b) a1

(c) 2a2

(d) a2

6 years ago

Answers : (2)

vikas askiitian expert
510 Points
										

we know , v = dx/dt


             a = dv/dt


    x = ao + a1t + a2t2


v= dx/dt =  0 + a1 + 2a2t


a=dv/dt = d/dt (a1+2a2t)


            =0+2a2 


differntiation of constant is 0...


so accleration of particle = 2a2


option c is correct

6 years ago
Vamsi Krishna Gedela
18 Points
										

x=a0+a1t +a2t2


accn=d2x/dt2=a2

6 years ago
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