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Shivam Bhagat Grade: 9
        A stone falls from a balloon that is descending at a uniform rate of 12m/s. the displacement from the stone from the point of release after 10 sec is

(a) 490 m

(b) 510m

(c) 610 m

(d) 725 m

6 years ago

Answers : (3)

jishnu prakash
15 Points

The point of release is a point in the air, not attached to the balloon.

Since speed of balloon has same direction as acceleration due to gravity,

u = 12m/s    a=9.8 m2/s  t=10s

s = ut  +  0.5at2 

  = 120   +   (0.5)(9.8)(100)

  = 610 m


6 years ago
vikas askiitian expert
510 Points

since the stone is falls from a stone which is decending with 12m/s

 that means unitial velocity of stone is given 12m/s .......

for constant accleration we have , s(displacement) = ut + at2/2

a = -g = -9.8m/s2(downward)      ,  u = -12m/s (downward)

             s = -12t - 9.8t2/2

after 10 sec

          s = -120-490=610m

option c is correct


6 years ago
21 Points
610 m
one year ago
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