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kedar joshi Grade: 10
        

a car is travelling on a straight road. the maximum velocity of the car can be 24m/s. the max. acceleration and max. deceleration it can attain are 1m/(second)square and 4m/(second)square respectively. the shortest time the car takes from rest to rest  in a distance of 200 mts is?

6 years ago

Answers : (1)

deeksha sharma
40 Points
										

The formula is


V(max) = (abt)/(a+b)


Here,a= Max acc


b= max decc


t= total time taken


Solving, we get 24=(1*4*t)/(4+1)


24*5=4t


t=30s

6 years ago
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