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Pooja singh Grade: 11
        

A block of mass 5 Kg is suspended from the end of a vertical spring which is stretched by 10cm under the load of the block. the block is given a sharp impulse from below so that it acquires an upward speed of 2m/s . How high will it rise?.........i


actually i saw the following equation in the solution



1/2kx2  + 1/2mv2 = ½(h – x)2 + mgh


i didn't understand how (h-x) can be written....................PLZ EXPLAIN


6 years ago

Answers : (1)

AKASH GOYAL AskiitiansExpert-IITD
419 Points
										

Dear pooja


See the pic for the solution


All the best.


AKASH GOYAL


AskiitiansExpert-IITD


 


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282_23499_Photo-0123.jpg

6 years ago
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