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WHEN THREE BLOCKS OF(DIFFERENT MASSES) ARE PLACED ON TOP OF ONE ANOTHER SUCH THAT THERE IS FRICTION(FRICTION COEFFICIENT DIFFERENT)BETWEEN ALL BLOCKS AND ALSO THE GROUND THEN HOW SHOULD I APPROACH THE PROBLEM WHEN THERE IS A FORCE APPLIED ON THE 2ND BLOCK AND I HAVE FIND THE ACCELERATIONS & THE FRICTIONAL FORCES?
WHEN I USE FRICTION=kN ;
I GET THE WRONG ANSWERS. PLEASE HELP!
1) consider the block which is under force. so apply newtons method for force equation.
sa applied force is F on that block.
here u= co efficeint
N= normal force
friction force f= U*N
F-f1-f3=m2*a
F-u1 * m1 *g-u3*m3*g= m2*a 2 ...... u1 is between m2 amd m1....u3 is between m2 and m3
apply same equations on 1st and 3rd blocks. the friction force direction is opposite to f1 and f3.
f3=m3*a3 = u3* m3*g
f3=m1*a1 = u1* (m3+m2+m1)*g
thanks
Rathod Shankar
IIT Bombay
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