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v=t/50 ( given)
dv/dt = at(tangential)=1/50
ar(centripital)=v^2/r = (t^2/2500r)
total accleration = sqrt ( (at)^2 + (ar)^2 )
total accleration is making an angle 60 with velocity vector ......velocity is parallel to tangential accleration so total accleration makes angle of 60 with tangential accleration...
a(total accleration)cos60 = a(tangential)
t= sqrt(3r) sec ( here r is the radius of circular path)
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