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With reference to above figure:
Find the acceleration of the block of mass M in the situation. All the surfaces are frictionless and the pulley and the string are light.
Dear Alpha
you have not given the wedge angle. assuming it to be theta
see the pic for the solution.
All the best.
AKASH GOYAL
AskiitiansExpert-IITD
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The equations are..For mass m is mgsina-T=m(2f) and for mass 2m is mg-2T=2m.f where a is angle of inclination and f is accelaration.From constraint it can be proved that booth will have same acc.
at mass 2M
2Mg-T=2Ma.............1
let the angle of incline be @
therefore at mass M
T-Mgsin@=Ma..........2
adding 1 and 2
2Mg-Mgsin@=3Ma
a=g(2-sin@)/3
accleration of mass M and 2M will be samel ......
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