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Chanchal Kumar Grade: 11
        

The relation between time t and position x along x-axis is given by t = ax^2 + bx, where a and b are alpha and beta and they are constants. Prove that the retardation is 2aV^3, where V is the velocity at time t.

6 years ago

Answers : (2)

vikas askiitian expert
510 Points
										

t = ax^2 + bx..............1


differentiate eq 1 wrt t


dt/dt = adx^2/dt + bdx/dt                    (dx/dt =V )


1=a(2xV) + bV...........2


again differnetiate wrt t


0=2a(xA+V^2)  + bA                          (dV/dt =A (retardation) )


A=-2Av^2 /2ax+b.................3


put the value of x in 3


A=-2Av^3


approve my ans if u like

6 years ago
NIKHIL GARG
38 Points
										

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6 years ago
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