Use Coupon: CART20 and get 20% off on all online Study Material

Total Price: Rs.

There are no items in this cart.
Continue Shopping
Vaibhav Mathur Grade: 12

A system is composed of 2 blocks of mass m1,m2 connected by a massless spring with  spring constant k.The blocks slide on a frictionless plane.The unstretched length of spring is l.Initially m2 is held so that the spring is compressed to l/2 and m1 is forced against a stop.M2 is released at t=0.Find the motion of the center of mass of the system as a function of time.

7 years ago

Answers : (1)

Chetan Mandayam Nayakar
312 Points

till spring assumes its stress free length, m2 executes SHM and m1 is stationary. the angular frequency is ω=√(k/m2),

the equation of motion of m2 in the SHM is x=l-(l/2)cos(ωt)

centre of mass=m2l(1-(cos(ωt)/2))/(m1+m2) for 0≤t≤(π/2)√(m2/k)

after that kinetic energy of centre of mass =kl2/8=(m1+m2)v2/2, v=(l/2)√(k/(m1+m2))

centre of mass =l+(t-(π/2)√(m2/k))(l/2)√(k/(m1+m2)) for t>(π/2)√(m2/k)

7 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete Physics Course - Class 12
  • OFFERED PRICE: Rs. 2,756
  • View Details
  • Complete Physics Course - Class 11
  • OFFERED PRICE: Rs. 2,968
  • View Details

Ask Experts

Have any Question? Ask Experts

Post Question

Answer ‘n’ Earn
Attractive Gift
To Win!!! Click Here for details