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Vishrant Vasavada Grade: 11
        

A particle is projected vertically upwards from a roof of a tower 60 m high with velocity 20 m/s. Find the average speed upto an instant when it strikes the ground. g = 10 m/s(sq)

6 years ago

Answers : (1)

vikas askiitian expert
510 Points
										

let T1 be the time taken by the particle to reach at the highest point 


 applying v=u-gT1  , v=0at the highest point ,u=20m/sec


   T1=2sec 


   let S1 be the distance covered during this period 


  then S1 = uT1-(gT1^2)/2


        S1=20m  


        same time is taken by particle to come at the point of projection


    now the velocity of particle becomes 20m/sec in downward dyrection 


      let time taken by particle to raech the ground is T2,again applying eq of motion


     -60=-20T2-(gT2^2)/2


    T2=2sec 


   total time =2T1+T2=6sec


   total distance=60+2.20=100 


   average speed =100/6=16.67m/s

6 years ago
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