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`        A particle is projected vertically upwards from a roof of a tower 60 m high with velocity 20 m/s. Find the average speed upto an instant when it strikes the ground. g = 10 m/s(sq)`
7 years ago

510 Points
```										let T1 be the time taken by the particle to reach at the highest point
applying v=u-gT1  , v=0at the highest point ,u=20m/sec
T1=2sec
let S1 be the distance covered during this period
then S1 = uT1-(gT1^2)/2
S1=20m
same time is taken by particle to come at the point of projection
now the velocity of particle becomes 20m/sec in downward dyrection
let time taken by particle to raech the ground is T2,again applying eq of motion
-60=-20T2-(gT2^2)/2
T2=2sec
total time =2T1+T2=6sec
total distance=60+2.20=100
average speed =100/6=16.67m/s
```
7 years ago
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