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```        1. A MAN THROWS THE BRICKS TO A HEIGHT OF 12 METER WHERE THEY REACH WITH A SPEED OF 12 M/S. IF HE THROWS THE BRICKS SUCH THAT THEY JUST REACH THAT HEIGHT, WHAT PERCENTAGE OF ENERGY WILL BE SAVED?
a)29%
b)46%
c)38%
d)50%
2. A FORCE F=(2i + j + 3k)N ACTS ON A PARTICLE OF MASS 1 Kg FOR 2 seconds. IF INITIAL VELOCITY OF PARTICLE IS
u= (2i +j) m/s, speed of particle at the end of 2s will be
a)12m/s
b)6m/s
c)9m/s
d)4m/s
saumya shivhare```
7 years ago

Chetan Mandayam Nayakar
312 Points
```										if speesd at 12m is 12m/s and bricks travel a further distance before coming to rest 122=2gh,h=7.2, therefore,energy saved =7.2/19.2= 38%
v=u+at
v= (2+(2*2))i +(1+(2*1))j +(3*2)k, therefore speed2 =36+9+36=81,speed=9m/s
```
7 years ago
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