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Dear Sneha,
ANS:-Let the velocity of the masses when the spring is again totally relaxesd is v, Then from the energy eq we get
1/2kd²=1/2(M1+M2)v²+(M1+M2)gdsinθ
Putting d=2/k(M1+M2)gsinθ & Solving we get v=0.
Hence the velocity is o, So, it will again compress the spring and let the comp is x then from energy eq we get,
(M1+M2)gsinθ x=1/2kx²
So again x=2(M1+M2)gsinθ/k
So, the two mass will execute Periodic motion with amplitude (M1+M2)gsinθ/k
THUS THEY WILL NEVER SEPARATE OUT
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Regards,
Askiitians Experts
SOUMYAJIT IIT_KHARAGPUR
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