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A ball is projected from the ground with a speed of 20m/s at an angle of 45° ith horizontal. There is a wall of 25m height at distance of 10m from the projection point. The ball will hit the wall at what height?
Dear sanket
As y = x tan α - gx2/2u2cos2α
put x=10
u=20
α=45
we get
y=10-10*100/(2*400*(1/2))
=7.5
At this height ball hits the wall
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