a particle of mass m, accelerated by a potential differece V flies through a uniform transverse magnetic field B. The magnetic field is spread in the thickness d. calculate the angle through which particle will deviate from the initial direction of motion.

Question

Pratham Ashish · Answer

hi ,

velocity of particle v = ( 2*q*V/m) ^1/2

^{& radius of path , r = m*v /q*B}

^{if d > r}

^{than particl will cover one half circle & will leave at 180 angle deviated from initial}

^{if d= r}

^{than particl will cover one fourth of circle & will leave at 90 angle deviated from initial}

^{if d < r}

^{than it will deviat an angle of sin^ -1 (d/r)}

^v

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a particle of mass m, accelerated by a potential differece V flies through a uniform transverse magnetic field B. The magnetic field is spread in the thickness d. calculate the angle through which particle will deviate from the initial direction of motion.

a particle of mass m, accelerated by a potential differece V flies through a uniform transverse magnetic field B. The magnetic field is spread in the thickness d. calculate the angle through which particle will deviate from the initial direction of motion.

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a particle of mass m, accelerated by a potential differece V flies through a uniform transverse magnetic field B. The magnetic field is spread in the thickness d. calculate the angle through which particle will deviate from the initial direction of motion.

a particle of mass m, accelerated by a potential differece V flies through a uniform transverse magnetic field B. The magnetic field is spread in the thickness d. calculate the angle through which particle will deviate from the initial direction of motion.

1 Answers

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