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how to integrate


from 0 to x

k,m&n are constants

6 years ago


Answers : (1)


Dear aman


we can also wrote


I = 1/m2n oxdx/[(k/m2n)-x]

    =  1/m2n oxdx/[a-x]            where a =(k/m2n)

 I= 1/m2n ox[a+x]dx/[a-x]

  I= 1/m2n ox[a]dx/[a-x]  +  1/m2n ox[x]dx/[a-x]

first part u can easly calculate

for second part  

 I2 = oxxdx/x[a-x]

put x = t

         dx = 2tdt

I2 = ox2t2dt/[a-t2]

this is also a standard form

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6 years ago

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