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Aman Rawat Grade: 12
        

Sir,


how to integrate


dx/[k-m{(2nx)^1/2}]


from 0 to x


k,m&n are constants

7 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
										

Dear aman


 oxdx/[k-m2nx]


we can also wrote


 


I = 1/m2n oxdx/[(k/m2n)-x]


    =  1/m2n oxdx/[a-x]            where a =(k/m2n)


 I= 1/m2n ox[a+x]dx/[a-x]


  I= 1/m2n ox[a]dx/[a-x]  +  1/m2n ox[x]dx/[a-x]


first part u can easly calculate


for second part  


 I2 = oxxdx/x[a-x]


put x = t


         dx = 2tdt


I2 = ox2t2dt/[a-t2]


this is also a standard form


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Badiuddin




 

7 years ago
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