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ROUDRAV CHAKRABORTY Grade: 12
        

∫√tan x

7 years ago

Answers : (1)

Menka Malguri
39 Points
										

Let tanx=t2,..................(1)


then differentiating both sides,we get,


sec2x dx=2t dt


(1+tan2x) dx=2t dt


(1+t4) dx=2t dt.................from(1)


dx=[2t/(1+t4)] dt


now,


∫√tanx


=∫√(t2).[2t/(1+t4)] dt


=∫[2t2/(1+t4)] dt


and solve further.


 

5 years ago
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