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				   d/dØ∫1/(1-cosxcosØ)dx


6 years ago

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										Ans:$I = \frac{d}{d\varnothing }\int \frac{1}{1-cosxcos\varnothing }dx$Using Leibniz’s rule, we have$I = \int \frac{\partial }{\partial \varnothing }(\frac{1}{1-cosxcos\varnothing })dx$$I = \int (\frac{-(cosxsin\varnothing) }{(1-cosxcos\varnothing)^{2} })dx$Thanks & RegardsJitender SinghIIT DelhiaskIITians Faculty

2 years ago

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