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integrate

∫1 ⁄ x(1+x2)1/2dx

6 years ago

Share

∫1 ⁄ x(1+x2)1/2dx

∫x ⁄ x2(1+x2)1/2dx

let (1+x2) =t2

xdx =tdt

so intigral become

∫1/t2 -1  dt

1/2 ln|t-1|/|t+1|  + C

1/2 ln|(1+x2)1/2-1|/|(1+x2)1/2+1|  + C

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6 years ago

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