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```				   solve  ∫|x+1| from limit -4 to 2 and explain
```

6 years ago

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```										First we have to remove the modulus sign befor integration.
Part 1:|x+1| is negative in the interval -4 to -1. therefore |x+1| becomes  -x-1
Part 2:and from the interval -1 to 2 |x+1| is x+1.
Therefore integrate |x+1| in above two parts.
```
6 years ago

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