if A denotes the area bounded by f(x)=mod (sinx+cosx whole divided by x),x axis ,x=Π and x=3Π the A what r the max and min value of A

2 years ago


Answers : (1)

Using the inequality
m(b-a)\leq \int_{a}^{b}f(x)dx\leq M(b-a)
a = \pi , b = 3\pi
m\leq f(x)\leq M
Max. value of A
2\pi M
Min. value of A
2\pi m
You can easily find the m & M from f(x) (I am not finding b/c f(x) is not clear)
Thanks & Regards
Jitender Singh
IIT Delhi
askIITians Faculty
7 months ago

Post Your Answer

More Questions On Integral Calculus

Ask Experts

Have any Question? Ask Experts
Post Question
Answer ‘n’ Earn
Attractive Gift
To Win!!!
Click Here for details
Hi Student The problem is not visible. Please post it again and limit as a sum is just conversion of integration to summation form. I will be able to explain more properly if you post the...
Harsh Patodia 3 months ago
please answer rest of the problems posted …....
bharat makkar 3 months ago
2 ∫ 0 (x 2 + 4) dx
Ans:- 2 ∫ 0 (x 2 +4)dx=[(x 2+1 /2+1 )+4x] --------- since (x n+1 /n+1) [(x 3 /3)+4x] 0 2 =[(2 3 /3)+8]=[(8/3)+3]=(8+24)/3=32/3
Anusha 3 months ago
Ans:- 2 ∫ 0 (x 2 +4)dx=[(x 2+1 /2+1 )+4x] --------- since (x n+1 /n+1) [(x 3 /3)+4x] 0 2 =[(2 3 /3)+8]=[(8/3)+3]=(8+24)/3=32/3
Anusha 3 months ago
evaluate the following integral ∫ sqrt((1 – sin 2x) / (1 + sin 2x)) dx
Ans: Hello student, Please find the answer to your question below
Jitender Singh 4 months ago
The number of points (x,y) (where x and y both are perfect squares of integers) on the parabola y^2=px,p being a prime number, is ?
y 2 = px y = sqrt(px) Since x & y are perfect square integers, sqrt(x) is an integer. Since p is a prime no., sqrt(p) is an irrational no. The point which satisfies the given condition is...
Y RAJYALAKSHMI 5 months ago
please explain scalar product and vector addition law?
scalar product is basically the product of two vectors and the cos of the angle between them. suppose ntwo vectors A and B its scalar or dot product will be A*Bcos (theta) where theta is the...
Sunil Kumar FP 9 months ago
No. of solutions of x,where x belongs to [0,2pie] and satisfies the equation, |sin a| +|cos a | = |sin x| where a is any real number. (Plz provide solution with explanation)
Solution: 2 Consider the left hand side of the equation and find its range. To do that let’s take its square ( |sin a| +|cos a |) 2 =sin 2 a+cos 2 a+|sin 2a| = 1 + |sin 2a| Since 0...
Sandeep Pathak 5 months ago
View all Questions »