Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```        S1. The area bounded by the curves y=x^2-3 and y=kx+2 is the least,if k=0.
S2:The area bounded by the curves y=x^2-3 and y=kx+2 is (k^2+20)^1/2.
a. is true;s2 is a correct explanation for S1.
b.S1 is true ;S2 is not a correct explanation for S1.
c.S1 is true,S2 is false
d.S1 is false,S2 is true```
8 years ago

Ramesh V
70 Points
```										The answer is : c.)S1 is true,S2 is false
The area bounded by the curves y=x2- 3 and y=2( for k=0 in y=kx+2)  is
2*integral of (y+3)1/2dy; limits from -3 to 2
area is 20*51/2/3

so for K=0 putting k=0 in S2 the area bounded does not come the same from formula (k^2+20)1/2 as in S2

So S1 is true,S2 is false

```
8 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Integral Calculus

View all Questions »
• Complete JEE Main/Advanced Course and Test Series
• OFFERED PRICE: Rs. 15,900
• View Details
Get extra Rs. 1,272 off
USE CODE: Neerajwin
Get extra Rs. 136 off
USE CODE: Neerajwin