MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
baha jaff Grade: 12
        

There is a line through the origin that divides the region bounded by the parabola y = 3 x - 8 x^2 and the x-axis into two regions with equal area. What is the slope of that line?

6 years ago

Answers : (1)

vikas askiitian expert
510 Points
										

let eq of line is y=mx            ...........1


eq of curve y = 3x-8x2           ................2


it will intersect the curve at P & Q ...


solving 1 & 2


x = 0 , (3-m)/8


y = 0 , m(3-m)/8


P = (0,0)  &  Q =[ (3-m)/8 , m(3-m)/8 ]


now x axis cuts the parabola at S = (3/8 , 0)


area bw parabola & x axis is A1 = (3x-8x2)dx         lim 0 to 3/8


                                              =9/128 units


now area bw line & parabola is A2 = (3x-8x2 - mx)dx       lim 0 to (3-m)/8


                                               = (3-m)3/384 units


now since x axis divides the area in two equal parts so


          A2 = 2 A1


       (3-m)3/384 = 2(9/128)


        (3-m)3 = 27*2


         m = 3(1-21/3)


 

6 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: Rs. 15,900
  • View Details
Get extra Rs. 3,180 off
USE CODE: CHEM20
Get extra Rs. 339 off
USE CODE: CHEM20

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details