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Chilukuri Sai Kartik Grade: 12
`        ∫dx/[sin(x/2)+Cos(x/2)]=?`
6 years ago

## Answers : (1)

510 Points
```										I = dx/[ sinx/2 + cosx/2 ]
=dx/21/2[(sinx/2)(1/21/2) + (cosx/2)(1/2)1/2]                   (multiplying dividing by 21/2)
=dx/21/2[(sinx/2)(cospi/4) + (cosx/2)(sinpi/4)]
=dx/21/2[sin(x/2+pi/4)]                                        (sina+b = sinacosb+cosasinb)
=cosec(x/2+pi/4)dx/21/2
=log[cosec(x+pi/4) -cot(x+pi/4)]  + c
```
6 years ago
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