Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        what is integration of 1/(a^2-2*a*cos(x)+1) its lower limit is 0 and upper limit is pie`
6 years ago

510 Points
```										I= dx/[a2 -2acosx +1]       lim 0 to pi
put cosx = 1-tan2x/2/1+tan2x/2
I= sec2x/2 dx / [(a-1)2 + (a+1)2tan2x/2]
now put tanx/2 = t
sec2x/2dx =2dt
I = 2dt / [(a-1)2+(a+1)2t2)
I =2dt/(1+a)2 .[(a-1/a+1)2 + t2]
this integral is same as  1/a2+x2 dx & its integral is tan-1(x/a)/a
so
I =2/(a2-1)tan-1[(a+1)t/(a-1)]
I = 2/(a2-1)tan-1[(a+1)tanx/2/(a-1)]               lim 0 tp pi
taking limit
I =2/(a2-1) [ tan-1infinity -tan-10]
=pi/(a2-1)         ans
```
6 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Integral Calculus

View all Questions »
• Complete JEE Main/Advanced Course and Test Series
• OFFERED PRICE: Rs. 15,900
• View Details