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Aparna Tiwari Grade: 12
        

integrate (1+tanx)dx/(1-tanx)

7 years ago

Answers : (1)

vikas askiitian expert
510 Points
										

I= {1+tanx/1-tanx}dx


I={(sinx+cosx)/(cosx-sinx)}dx


put cosx-sinx=t then after differentiatng


(sinx+cosx)dx=-dt


I=-dt/t


I=-logt + c


I=-log(cosx-sinx) + c

7 years ago
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