the ionization constant of a base [C2H5]3N is 6.4x 10to d power minus 5. calculate its degree of dissociation in its 0.1 M solution when it is mixd with 0.01 M NaOH solution.

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Mugdha Pawar · Answer

degree of dissociation = ionization const /concentration by common ion effect =6.4*10^-5/0.01 =6.4*10^-3

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the ionization constant of a base [C2H5]3N is 6.4x 10to d power minus 5. calculate its degree of dissociation in its 0.1 M solution when it is mixd with 0.01 M NaOH solution.

the ionization constant of a base [C2H5]3N is 6.4x 10to d power minus 5. calculate its degree of dissociation in its 0.1 M solution when it is mixd with 0.01 M NaOH solution.

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the ionization constant of a base [C2H5]3N is 6.4x 10to d power minus 5. calculate its degree of dissociation in its 0.1 M solution when it is mixd with 0.01 M NaOH solution.

the ionization constant of a base [C2H5]3N is 6.4x 10to d power minus 5. calculate its degree of dissociation in its 0.1 M solution when it is mixd with 0.01 M NaOH solution.

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