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The geometry of Ni(CO)4 and Ni(PPh3)2Cl2 are what and why? Chapter --- Coordination compounds

The geometry of Ni(CO)4 and Ni(PPh3)2Cl2 are what and why? Chapter --- Coordination compounds

Grade:11

2 Answers

Umakant biswal
5349 Points
7 years ago
@ anikesh 
the geometry of Ni(c o)4 is tetrahedral , and the geometry of Ni9pph3)2cl2 are square planer . 
Reason – ni(co) 4 is a unusual complex , it has ni in 0 oxidation state , thus there are 8 electrons in 3d aND 2 electrons in 4s . co is the strongest ligand and does cause pairing by leaving 1 empty d orbital . now , the pair electron is 4s shift to 3d leaving 4s orbital empty . and free to accomdate electrons from co . so, there are no free d orbital as its a weak ligand , so, it has sp3 hybridisation . meaning tetrahedral shape . 
HOPE IT CLEARS YOUR DOUBT 
ALL THE BEST ,.,
Rishi Sharma
askIITians Faculty 646 Points
3 years ago
Dear Student,
Please find below the solution to your problem.

Ni(CO)4​: CO is the strongest ligand and does pairing which leaves 1 empty d orbital, but somehow, electron from the s orbital jumps to d orbital leaving 4s orbital empty to accomodate electrons from CO. Therefore geometry of Ni(CO)4​ is tetrahedral. Hybridisation is sp3.
[Ni(PPh3​)2​Cl2​]: The oxidation number of ni is +2. PPh3​ is a strong ligand and does pairing which leaves 1 empty d orbital, so electrons from CO will come in 3d orbital as well as 4s orbital and thus, the geometry is square planar. Hybridisation is sp3d2

Thanks and Regards

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