The amount of energy released when 10 to the power 6 atoms of iodine in vapour state are converted to I - ions is 4.9 x 10 -13 J what tis the electron affinity of iodine in eV per atom?

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Sakshi · Answer

In this question, we are given that on the conversion of 106 molecules of I2 to I- , the amount of energy released is 4.9*10-13 J
On using the concept of unitary method, one can also find the amount of energy released for the avagadro number of molecules of iodine. Finally we can use the interconversion factor as 1eV= 1.6*10-19 J
Using these values, one can easily get the answer to the question

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The amount of energy released when 10 to the power 6 atoms of iodine in vapour state are converted to I - ions is 4.9 x 10 -13 J what tis the electron affinity of iodine in eV per atom?

The amount of energy released when 10 to the power 6 atoms of iodine in vapour state are converted to I^- ions is 4.9 x 10^-13 J what tis the electron affinity of iodine in eV per atom?

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The amount of energy released when 10 to the power 6 atoms of iodine in vapour state are converted to I - ions is 4.9 x 10 -13 J what tis the electron affinity of iodine in eV per atom?

The amount of energy released when 10 to the power 6 atoms of iodine in vapour state are converted to I- ions is 4.9 x 10-13 J what tis the electron affinity of iodine in eV per atom?

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The amount of energy released when 10 to the power 6 atoms of iodine in vapour state are converted to I^- ions is 4.9 x 10^-13 J what tis the electron affinity of iodine in eV per atom?