Use Coupon: CART20 and get 20% off on all online Study Material

Total Price: R

There are no items in this cart.
Continue Shopping
Get instant 20% OFF on Online Material.
coupon code: MOB20 | View Course list

Get extra R 280 off


sir... i hv studied p,d block only from ncert.... nd not having confidence on it for jee2010. guide me some way to tackle inorg ques in jee2010... ll b greatly thankful to u.....

6 years ago


Answers : (1)


Dear jainish

The complexity of the IIT-JEE arises from the fact that the questions are always unique in their context, and solving them

often requires a combination of concepts from across different chapters.

First of all u be clear in ur conceptual understanding and then concentrate on solving various questions from different study

materials. Dont loose ur confidence. Work hard and utilize the time available effectively. Also utilize the faculties of the

coaching centres to know about the techniques of solving the problems and also the what kind of study materials can give the problems which are more related to the JEE exams

Y r prepearnig for IIT JEE ,so it is quite natural that u will forget tings,so u should keep revise and revise after certain interval of time.inorganic chemistry is simple as comapir to the other part of chemistry,but it needs more time .you have to refer many question from different material and books.

'Inorganic Chemistry' and 'General Chemistry' account for 21% and 10% of the total marks. Inorganic Chemistry should be

prepared by studying the group properties and periodicity. Lots of emphasis has to be given to Exceptions. Questions are

asked from these topics invariably. The properties of some important compounds are also asked in the form of reactions.

Remembering the reactions involved in qualitative analysis is of great advantage. Questions asked in General Chemistry mostly

include that from 'Stoichiometry' and 'Chemical Bonding'
Just stay calm and focus on understanding rather than mugging. Be regular in class and stay with concepts

Please feel free to post as many doubts on our discussion forum as you can.
If you find any question Difficult to understand - post it here and we will get you
the answer and detailed solution very quickly.
 We are all IITians and here to help you in your IIT JEE  preparation.

All the best.
Askiitians Experts

6 years ago

Post Your Answer

Other Related Questions on Inorganic Chemistry

sir please explain in short what do you mean by Bridging ligands ??
Hi ! Prasan ,, A Bridging ligand is defined as the one that can simultaneously bond itself to more than one metal ion.OH- , Cl- , NH2- , can function both as monodentate and bridging ...
raju 2 months ago
@prasan an atomic or polyatomic ligand which connect two or more atoms in a compound is called bridging ligand . example – nbcl5 these are 2 bridging and 8 terminal chloride ligand . HOPE...
Umakant biswal 2 months ago
Why Hydrogen Sulphide precipitates Zinc Chloride in neutral medium & not in acidic medium.
@ gagandeep kindly see the below reaction zncl2 + hc = 2hcl + zns then its a double displacement reaction . as its a double displacement reaction , it cannot have suitable condition in...
Umakant biswal 2 months ago
state kohlrausch law of independent migration of ions? write one of its application ?
This law states that the limiting molar conductivity of an electrolyte can be represented as the sum of the individual contributions of its anion and cation. Applications of Kohlrausch 's...
SAHIL 20 days ago
examples for stereo centres which are not chiral centres
Dear student Stereocentre- If there is no plane of symmetry in the molecule of an organic compound, we say it is having a stereocentre. Chiral Centre/Chiral Carbon Atom - If in a moelcule...
Bhavya one month ago
how to balance following redox reaction in basic medium. C 4 H 4 O 6 2- +ClO 3 - =CO 3 2- +Cl - Please, balance with complete steps.
Balance C 4 H 4 O 6 2- + ClO 3 1- = 4CO 3 2- + Cl 1- C 4 = +6 Cl = +5 4C = +16 Cl = -1 Hence from the above calculation of oxidation no. C shows oxidation by 10 and Cl undergoes reduction...
Prachi 14 days ago
3C 4 H 4 O 6 2- + 5ClO 3 1- + 18OH - = 12CO 3 2- + 5Cl - [ H = 30, O = 51] [ H = 0, O = 36] Due to deficiency of hydrogen and oxygen on right side we add 15H 2 O on the right side Final...
Prachi 14 days ago
Why do we prefer Friedel craft acylation to Friedel craft alkylation in preparation of alkylbenzene?
There are many electrophilic substitution reactions associated with benzene and benzene derivatives. However, very few of them involve formation of a carbon-carbon bond, one of the primary...
dolly bhatia 2 months ago
Friedel craft acylation inviles always the double bonded Oxygen with R or other group which leads to decrease in the density of the electrons. .Where as alkyl group -R shows +I effect which ...
Vikas TU 2 months ago
View all Questions »

  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: R 15,000
  • View Details
Get extra R 3,000 off

Get extra R 280 off

More Questions On Inorganic Chemistry

Ask Experts

Have any Question? Ask Experts

Post Question

Answer ‘n’ Earn
Attractive Gift
To Win!!!
Click Here for details