Use Coupon: CART20 and get 20% off on all online Study Material

Total Price: R

There are no items in this cart.
Continue Shopping
Get instant 20% OFF on Online Material.
coupon code: MOB20 | View Course list

Get extra R 350 off

				   "equivalent and milliequivalent react in equal no to give the same no of eq or Meq of products" what does this statement mean? please explain with example.

6 years ago


Answers : (1)


Chemical substances donot react with each other in terms of moles. It means, 1 mole of A may react with 2 moles of B or with 3 moles of C or with X moles of Z. The proportion in which they react is uncertain, until and unless you know the stoichiometry of the reaction.

To avoid this ambiguity of proportions of reactants, chemists introduced the concept of Equivalent weights. Always one equivalent of one substance reacts with one and only one equivalent of the other substance. Means, chemical substances react in terms of their equivalents (or milli equivalents) and not in terms of moles. 

Gram equivalent of an acid, base, reductant  or oxidant is the mass of substance in gram that can transact Avagadro number of electrons. So, 1 equivalent of acid reacts with 1 eq of base or 1 eq of reductant reacts with 1 eq of oxidant. 

6 years ago

Post Your Answer

Other Related Questions on Inorganic Chemistry

what meant stationary and rotating polarcovalent molecule ?
@ mardana the covalent molecules which have dipole moment as 0 are called as stationary polar covalent molecules . there are also no degree of freedom of these molecules . rotating polar...
Umakant biswal 8 days ago
Is the complex Co[(Nh3)2(h20)4] is paramagnetic or diamagnetic
U would have to find the configuration and hybridization .of Co. then count the numver of d-electrons according to tyhe Bonding and Antibonding table as per given in the NCERT book and then ...
Vikas TU 2 months ago
Liquation of which gaseous substance will arise as a result of momentum imbalance in electronic distribution? (1) Ammonia (g) (2) Carbon dioxide (g) (3) Na+(g) Cl–(g) (4) Xenon (gas)
But bro! the answer is not that.... Answer given is Xe...and I feel the question is taking about London dispersive forces, hence the answer may be Xe...
Giri sripathi 24 days ago
(3) option. Na+ (g) Cl- (g) as only this compounnd is inic in nature. Rest are covalent ones like NH3 , Xe(g) and CO2.
Vikas TU 24 days ago
What is the radius of Li 2+ ion in 2nd orbit and please give me the formula
@ piyush u haVE to use the below formula r (n ) = n ^ 2*0.529* 10^ -10 / zm z = atomic number = 3 n = 2 (as given 2 nd orbit ) just put the value in the formula and calculate it . r (n ) =...
Umakant biswal one month ago
The formula of finding the radius of atom = 0.529 * n^2/Z So, here the ‘n’ is 2 & ‘Z’ is 3 Then, Radius=0.529 * 4/3 =0.705
Lakshit one month ago
how to balance following redox reaction in basic medium. C 4 H 4 O 6 2- +ClO 3 - =CO 3 2- +Cl - Please, balance with complete steps.
Balance C 4 H 4 O 6 2- + ClO 3 1- = 4CO 3 2- + Cl 1- C 4 = +6 Cl = +5 4C = +16 Cl = -1 Hence from the above calculation of oxidation no. C shows oxidation by 10 and Cl undergoes reduction...
Prachi 10 days ago
3C 4 H 4 O 6 2- + 5ClO 3 1- + 18OH - = 12CO 3 2- + 5Cl - [ H = 30, O = 51] [ H = 0, O = 36] Due to deficiency of hydrogen and oxygen on right side we add 15H 2 O on the right side Final...
Prachi 10 days ago
How do we find the bond order in a compound.......?
1- Draw the Lewis structure. 2-count the total no of bond . 3-count the no of bond group between individual atom . 4-divide the no of bond between atoms by a total no of bond group in the...
Umakant biswal one month ago
you have already familiar with text books of intermediate. take reference from that text book .use this oppurtunity for only asking critical questions. It makes you perfect in writing JEE...
cris gayle one month ago
View all Questions »

  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: R 15,000
  • View Details
Get extra R 3,750 off

Get extra R 350 off

More Questions On Inorganic Chemistry

Ask Experts

Have any Question? Ask Experts

Post Question

Answer ‘n’ Earn
Attractive Gift
To Win!!!
Click Here for details