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IF THE MAXIMUM & MINIMUM VALUE OF -
y= x2-3x+c / x2+3x+c ARE 7 AND 1/7 ,THEN VALUE OF c IS ...?
Dear rahul
y= x2-3x+c / x2+3x+c
cross multiply and simplify
x2(y-1) +x(3y+3) +c(y-1)=0
this equation has a real value so discrimnent will be ≥ o
(3y+3)2 -4c(y-1)(y-1)≥0
simplyfy
{y(3+2√c) -(2√c-3)}{y(2√c -3) -(3+2√c)}≤0
(2√c-3)/ (3+2√c) ≤ y≤(3+2√c)/(2√c -3)
compair with given condition
(3+2√c)/(2√c -3) =7
c= 9/4
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