A light ray is incident on a prism in minimum deviation position and suffers a deviation of 34 degree. If the shaded half of the prism is removed off, then the same ray will suffer a deviation of?

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Vikas TU · Answer

By formula δ=(n−1)A⇒34=(n−1)A and in the second position δ′=(n−1)A/2 ∴34/δ′=(n−1)A/(n−1)A/2 or δ′=34/2=17∘

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A light ray is incident on a prism in minimum deviation position and suffers a deviation of 34 degree. If the shaded half of the prism is removed off, then the same ray will suffer a deviation of?

A light ray is incident on a prism in minimum deviation position and suffers a deviation of 34 degree. If the shaded half of the prism is removed off, then the same ray will suffer a deviation of?

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A light ray is incident on a prism in minimum deviation position and suffers a deviation of 34 degree. If the shaded half of the prism is removed off, then the same ray will suffer a deviation of?

A light ray is incident on a prism in minimum deviation position and suffers a deviation of 34 degree. If the shaded half of the prism is removed off, then the same ray will suffer a deviation of?

1 Answers

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