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                   hello,sir hi my name is raghavendra charn kumar.sir i am applying for iit-jee.but till now i didn't receive my admit card.i am a poor student.firlst of all i didn't send  all relavent documents to iit-jee office.we are belonging to iit-jee madras zone.i didn't my ssc marks list with my iit application.but after viewing the application status in iit-jee madras it shows that your application has not received.i am worried about my application.my application number is A361017003.one thing is sir after viewing the status i will send my ssc certificate to iit-jee office.i will call to iit chairman .he says that your application has been received to me.there is no worry about it.but till now i didn't receive my admit card.sir could you please help me sir.i kindly request you sir pl z help me.in hard copy of application status it shows that your application information is in our database.so with these problems i have a lot of confusion whether is it reach or not to the iit office or whether they send or not my admit card.once again i request you sir please help me to my problem.thank you sir. i hope you will send response to my question.or send iit official officers mail addresses(or)phone numbers.i beg you sir so what can i do now.

5 years ago

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after passing 9 th what i have to do for my iit career?
 
 
Hello Student, ITs very good that you have started so early. For JEE your foundation base should be very strong. Right now you can prepare for exams like NTSE, Olympiad, KVPY , etc which...
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Nishant Vora one month ago
 
Hi Student, Please enroll for askiitians classes if you want iitjee level preparation from 9 th class.
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Harishwar one month ago
Next number 2, 5, 11, 20, 32, 47?
 
 
Yeah absolutely keep adding the multiples of 3 in your given series. 3+2=5 6+5=11 9+11=20 12+20=23 15+32=47 18+47=65 So the next number will 65.
 
vikas yadav one month ago
 
3 rd on1: Solution: i) t₂ - t₁ = 5 - 2 = 3 t₃ - t₂ = 6 t₄ - t₃ = 9 and so on... So let the nth term - (n-1)th term be = x. ii) Sum of all the above = nth term - t₁ = 3 + 6 + 9 + ----- [This...
 
vikas yadav one month ago
 
second method: Series 2, 5, 11, 20, 32, 47 Find = next number In this series each digit has the difference of 3,6,9,12,15 etc.. so next series will have the difference of 18. It means next...
 
vikas yadav one month ago
I’ve dropped after 12 th after I was unable to Qualify for 1 st attempt in JEE-Advanced (because of New Pattern I have not cleared the cut-off for JEE-Advanced). Second time I was unable to...
 
 
You cannot appear as fresher as for JEE as you have already appeared twice for JEE. As far as your dream of doing research in IIT, you can still achieve that dream. For now you can take...
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Aziz Alam 8 months ago
 
Thanks AZIZ :) This is a great suggestion for me Dear...but It’s better to remove doubts at all..haina So I am on your advice to take admission in some Good College... Actually the Problem...
 
HImanshu 8 months ago
 
Hey Himanshu, Getting into MIT or other good foreign university require good SAT score plus a strong academic background. Usually strong background means good scores in school level exams...
 
Rakesh Singh 8 months ago
i have scored 184 marks in MAINS AND EXPECT 94% MARKS IN 12TH BY CBSE WHAT IS MY EXPECTED RANK IN MAINS SCORE
 
 
Go to this link and try to find out everything you want to know about your JEE Main 2015 performance....
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Aziz Alam 7 days ago
 
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ng29 6 days ago
SIR I HAVE PASSED MY CLASS 12TH THIS YEAR,THAT IS IN 2014.IF I APPEAR FOR JEE-ADVANCE NEXT YEAR,WILL THE BOARD PERCENTILE WHICH IS 83.2% THIS YEAR WILL BE CONSIDERED OR THE PERCENTILE...
 
 
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Ramreddy 9 months ago
suggest books for practice questions
 
 
“suggest books for practice questions“ which book you are talking about.Please be specific while posting your answer.Please specify the class which you are in.Wether competitve...
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Sunil Kumar FP 6 months ago
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